Author Topic: Cheap F96T12 striplight ballasts  (Read 453 times)
BlueHalide
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Cheap F96T12 striplight ballasts « on: May 18, 2017, 10:24:15 PM » Author: BlueHalide
Just thought ide mention this...The Lithonia 2x F96T12 striplights that Menards recently clearanced appears to underdrive the lamps considerably. I bought two of them, and both measured 104w-106w when operating full power 75w lamps, after installing 60w miser lamps the power still measured the same. 104w is only 52w per lamp assuming no ballast losses. I thought the lamps appeared quite dim to begin with, and the watt-meter just confirmed it. Ive always known the modern electronic T12HO's to run at a 20% reduction or so, but this is the first time ive seen standard normal output being underdriven like this. Dont use your vintage F96T12's in these fixtures!
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Ash
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Re: Cheap F96T12 striplight ballasts « Reply #1 on: May 19, 2017, 02:10:21 AM » Author: Ash
Is there ballast factor rating printed on the ballast ?
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BlueHalide
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Re: Cheap F96T12 striplight ballasts « Reply #2 on: May 19, 2017, 01:43:54 PM » Author: BlueHalide
only "high power factor" is printed, but who knows what the PF really is.
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Ash
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Re: Cheap F96T12 striplight ballasts « Reply #3 on: May 19, 2017, 11:51:20 PM » Author: Ash
Power factor is not same as ballast factor

Power factor = actual power drawn from supply / apparent power drawn from supply

Ballast factor = actual power delivered to lamp / rated power
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Lightingguy1994
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Re: Cheap F96T12 striplight ballasts « Reply #4 on: June 30, 2017, 01:05:45 PM » Author: Lightingguy1994
I also didnt know there was a difference between ballast factor and power factor. how do you measure ballast factor?
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HomeBrewLamps
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Re: Cheap F96T12 striplight ballasts « Reply #5 on: June 30, 2017, 01:42:52 PM » Author: HomeBrewLamps
ballast factor is the measurement of lumen output of lamps on that ballast compared to the lumen output of those lamps on a reference ballast

power factor is basically just measuring how efficiently the lighting is applying the power it is using.


correct me if im wrong there....
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Re: Cheap F96T12 striplight ballasts « Reply #6 on: August 06, 2017, 09:19:34 AM » Author: xmaslightguy
Quote from: BlueHalide
appears to underdrive the lamps considerably.
 only 52w per lamp assuming no ballast losses.
If they have the same wiring as a F96 T8 electronic, maybe they could be wired for overdrive...
Giving 78 (or maybe 90w if its a good ballast) watts for 1 lamp (also assuming zero ballast losses). So could end up being a perfect match.
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Ash
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Re: Cheap F96T12 striplight ballasts « Reply #7 on: August 06, 2017, 11:46:59 AM » Author: Ash
power factor is basically just measuring how efficiently the lighting is applying the power it is using
Power factor is how much power the ballast is actually using vs the load on the supply



For example :

You plug in an 1200W convection space heater, which is essentially a Steel wire with total resistance of 12 Ohm, assembled in a device that lets it heat up and dissipate this heat into the air

120V / 12 Ohm = 10A

120V * 10A = 1200W

The space heater uses 1200W of power, and draws 10A from the line



Now take a 220uF capacitor

Xc = 1 / ( 2pi f c ) = 1 / ( 2pi * 60Hz * 220uF ) = 12 Ohm

120V / 12 Ohm = 10A

120V * 10A = 1200W

Plug in the 220uF capacitor into 120V. Just the capacitor, with nothing else. It will pass 10A, but won't do anything with power (i.e. it won't heat up, converting electrical power to heat power)

The capacitor is drawing 10A, same as if it would be 1200W heater, but it does not actually use the power. It does not take the power and convert it to heat, light, mechanical work or anything like that. It does not get wasted to losses either. All it does is charge and discharge back into the line on every half cycle of the AC, 120 times/sec


So, is the capacitor actually drawing 1200W or not ?

If we measure the current, we see that there are 10A flowing. Apparently it looks like if 120V * 10A = 1200W load is connected and drawing power. This is Apparent power

 - The wiring, circuit breakers, and all that have to be sized to handle the 10A, because 10A really flow in the circuit



If we measure the power used (and not returned into the line), it is 0. This is the real power

 - The meter does not spin for the capacitor

 - The power plant's turbine load (so by extension, the fuel use. pollution etc) are not increased by the capacitor's presence



The relation between the power really used (real power) and the "would be" power that is calculated from the current x voltage (apparent power) is the power factor

For a resistor like the heater, the real power = apparent power, PF = 1

For the capacitor, the real power is 0, PF = 0

For something else, it is something inbetween



How efficiently the ballast uses the power (ie. the part delivered to the lamp vs. the part in the losses) is efficiency, this have nothing to do with power factor. There can be a combination of any efficiency with any power factor



also assuming zero ballast losses
In case of Electronic ballast driving a lamp rated for Magnetic ballast, this is allmost the case. There are ballast losses, but at high frequency less power is needed to get the same output from the lamp

So for example, a 40W lamp powered by say 36W at HF will be as bright as 40W lamp powered by 40W from magnetic ballast. This gives 4W of "hidden headroom" for ballast losses, bc/ for example if the HF ballast have 4W losses, the complete lamp+ballast system will use 40W and light like proper 40W. so it behaves as if the ballast indeed have no losses

Most Electronic ballasts are not quite that efficient but the difference amounts to single watts
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