| I am not sure about American CWA practice, but in the world of fluorescents, leading ballasts roughly have the capacitor impedance about twice of the choke impedance. That way, choke inductance cancels about 1/2 of the capacitor impedance, and you end up with a leading ballast with about the same impedance as the choke intended for lagging circuit. Important: this is true only for the 1'st harmonic.
So you likely can try to calculate a capacitor having 2X of the nominal impedance of your M90 ballast, and then decrease it just slightly to adjust to the proper current. This is of course somewhat simplified by not accounting for the choke resistance.
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« Last Edit: June 23, 2026, 05:17:29 PM by RRK »
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