By the way, is low current cold cathode mode for instant start electronic ballasts prolong the electrodes life when comparing to high current cold cathode?
It is not as simple answer.
- The real cold cathode wear progress is proportional with amount of ions, so with multiplying current and time, provided the temperature profile is constant
- Higher current mean, higher temperature is necessary to handle it in "hot cathode" mode, so the electrode need more heat to reach such temperature, what prolong the duration of the cold-cathode mode, so increase the associated wear.
- Lower current mean more significant is amount of heat radiated away from the electrode, what prolong the duration of the cold-cathode mode, so increase the associated wear. Moreover relatively longer time is spent in the phase, where the temperature is high (so materials are weaker and easier to sputter away), but still not high enough to reach emission necessary to lower the cathode drop.
I would say there would be somewhere an optimum, but i doubt somebody really care of reaching it - instant start are designed or to be cheap (so nobody care as much for the lifetime) or for applications with long burning hours per start, where the starting related wear is not a factor, unlike the extra power dissipation for "better" ballasts.
It is ironical, then those simple, selfoscillating, instant start ballasts are those most energy efficient. There are two reasons: First, they do not heat up filaments (about 1W for F36T8), seconds, there is no controller needing it's supply (~1W for most controllers) and thirds, the selfoscillating concept allow the use of bipolar transistors, what have way lower "equivalent Ron", so associated losses, while their slowness is not an issue, as these ballast work in "soft switching" mode, entirely eliminating (otherwise high for bipolars) switching losses, so MOSes loose the game... Issue is, then those more advanced IC's are not able to drive bipolar transistors (or it would require more supply power for the controller), so they are stuck with otherwise more lossy FET's.